Respostas AVA

Para o Teorema Geral de Fourier, bn equivale a:

$\displaystyle\frac{{1}}{{{2}.\pi}}.{\int_{{d}}^{{{d}+{2}.\pi}}}{f{{\left({t}\right)}}}.{\left.{d}{t}\right.}$
$\displaystyle{n}.{d}.{a}$
$\displaystyle\frac{{a}_{{{0}}}}{{2}}+{\sum_{{{n}={1}}}^{\infty}}{\left({a}_{{{n}}}.{\cos{{\left({n}.{w}_{{{0}}}.{t}\right)}}}+{b}_{{{n}}}{s}{e}{n}{\left({n}.{w}_{{{0}}}.{t}\right)}\right)}$
$\displaystyle\frac{{1}}{\pi}.{\int_{{d}}^{{{d}+{2}.\pi}}}{f{{\left({t}\right)}}}.{s}{e}{n}{\left({n}.{t}\right)}.{\left.{d}{t}\right.}$
$\displaystyle\frac{{1}}{\pi}.{\int_{{d}}^{{{d}+{2}.\pi}}}{f{{\left({t}\right)}}}.{\cos{{\left({n}.{t}\right)}}}.{\left.{d}{t}\right.}$

PRINCÍPIOS DE COMUNICAÇÃO

Para o Teorema Geral de Fourier, bn equivale a: