Respostas AVA

CÁLCULO III

$\displaystyle\frac{{{d}{F}}}{{{\left.{d}{t}\right.}}}={2}{{e}}^{{{2}{t}}}-{9}{{t}}^{{2}}$
$\displaystyle\frac{{{d}{F}}}{{{\left.{d}{t}\right.}}}={2}{{e}}^{{t}}-{9}{{t}}^{{2}}$
$\displaystyle\frac{{{d}{F}}}{{{\left.{d}{t}\right.}}}={2}{{e}}^{{{2}{t}}}+{{t}}^{{2}}$
$\displaystyle\frac{{{d}{F}}}{{{\left.{d}{t}\right.}}}={2}{{e}}^{{{2}{t}}}+{9}{{t}}^{{2}}$
$\displaystyle\frac{{{d}{F}}}{{{\left.{d}{t}\right.}}}={{e}}^{{t}}+{9}{{t}}^{{2}}$