CIRCUITOS ELÉTRICOS II
A figura abaixo mostra o circuito equivalente monofásico de um sistema trifásico, sequência de fases ABC, a três condutores, que alimenta duas cargas, (1) e (2). Equacionando o circuito pode-se afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM07_Q7.jpg)
A reatância indutiva da carga (1) é igual a 2 â¦.
O defasamento da corrente que circula pela fase C do sistema é menor que 80°.
O valor, em módulo, da corrente que circula pela impedância ZAB da carga (1) é maior que 17 A.
O valor do módulo da tensão de linha na carga (2) é maior que 220 V.
O valor do módulo da corrente na linha B é menor que 50 A.
Uma fonte trifásica equilibrada, com tensão de linha igual a 240 V eficazes, fornece 8 kVA com fator de potência igual a 0,6 atrasado, para duas cargas ligadas em estrela, em paralelo. Sabendo que uma das cargas absorve 3 kW com fator de potência unitário e que a linha não possui impedância, pode-se afirmar que:
O valor do módulo da impedância da carga desconhecida é maior que 9 Ω.
O valor, em módulo, da corrente na linha é maior que 19 A.
O valor, em módulo, da corrente de fase da carga conhecida é menor que 7 A.
O fator de potência da segunda carga é igual a 0,6, atrasado.
O reativo total absorvido pela carga desconhecida é maior que 6,5 kVAr.
Uma carga equilibrada, ligada em triângulo, absorve 5 kW de um sistema trifásico cuja tensão eficaz da linha é igual a 400 V. Sendo o fator de potência da carga igual a 0,8, atrasado, é correto afirmar:
Se as três impedâncias da carga fossem ligadas em estrela o valor da potência aparente total absorvida seria igual a 1/3 do valor da ligação em triângulo.
O valor do módulo da corrente de fase na carga é menor que 5,0 A.
O valor da resistência da impedância é menor que 60 Ω.
A potência aparente trifásica absorvida pela carga é maior que 6,5 kVA.
O valor, em módulo, da queda de tensão sobre a indutância da impedância é maior que 250 V.
Um aluno encontrou uma bobina e quis determinar o valor de sua resistência interna Rbob e de sua indutância Lbob. Para tanto, conectou em série com a bobina uma resistência Rs = 10 Ω. Ele ligou o conjunto num varivolt e aplicou nele uma tensão de 36 V, eficazes, em 60 Hz. Com um voltímetro, mediu a tensão sobre o resistor, obtendo Vs = 20 V e sobre a bobina, obtendo Vbob = 22,4 V. Com os resultados obtidos fez os cálculos e concluiu que:
A tensão fasorial do varivolt deve ser escrita como Vvar = 36 /+40° V.
A bobina possui uma indutância menor que 30 mH.
A resistência da bobina é maior que 8 Ω.
A potência dissipada pelo resistor Rs é igual a 50 W.
Adotando a tensão Vs como referência, o ângulo da impedância da bobina é menor que 60°.
Determine o valor de YT.
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Assinale a alternativa que corresponde a reposta.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
![](http://sga.uniube.br/images/uploads/5105/SEM07_Q7.jpg)
A reatância indutiva da carga (1) é igual a 2 â¦.
O defasamento da corrente que circula pela fase C do sistema é menor que 80°.
O valor, em módulo, da corrente que circula pela impedância ZAB da carga (1) é maior que 17 A.
O valor do módulo da tensão de linha na carga (2) é maior que 220 V.
O valor do módulo da corrente na linha B é menor que 50 A.
Uma fonte trifásica equilibrada, com tensão de linha igual a 240 V eficazes, fornece 8 kVA com fator de potência igual a 0,6 atrasado, para duas cargas ligadas em estrela, em paralelo. Sabendo que uma das cargas absorve 3 kW com fator de potência unitário e que a linha não possui impedância, pode-se afirmar que:
O valor do módulo da impedância da carga desconhecida é maior que 9 Ω.
O valor, em módulo, da corrente na linha é maior que 19 A.
O valor, em módulo, da corrente de fase da carga conhecida é menor que 7 A.
O fator de potência da segunda carga é igual a 0,6, atrasado.
O reativo total absorvido pela carga desconhecida é maior que 6,5 kVAr.
Uma carga equilibrada, ligada em triângulo, absorve 5 kW de um sistema trifásico cuja tensão eficaz da linha é igual a 400 V. Sendo o fator de potência da carga igual a 0,8, atrasado, é correto afirmar:
Se as três impedâncias da carga fossem ligadas em estrela o valor da potência aparente total absorvida seria igual a 1/3 do valor da ligação em triângulo.
O valor do módulo da corrente de fase na carga é menor que 5,0 A.
O valor da resistência da impedância é menor que 60 Ω.
A potência aparente trifásica absorvida pela carga é maior que 6,5 kVA.
O valor, em módulo, da queda de tensão sobre a indutância da impedância é maior que 250 V.
Um aluno encontrou uma bobina e quis determinar o valor de sua resistência interna Rbob e de sua indutância Lbob. Para tanto, conectou em série com a bobina uma resistência Rs = 10 Ω. Ele ligou o conjunto num varivolt e aplicou nele uma tensão de 36 V, eficazes, em 60 Hz. Com um voltímetro, mediu a tensão sobre o resistor, obtendo Vs = 20 V e sobre a bobina, obtendo Vbob = 22,4 V. Com os resultados obtidos fez os cálculos e concluiu que:
A tensão fasorial do varivolt deve ser escrita como Vvar = 36 /+40° V.
A bobina possui uma indutância menor que 30 mH.
A resistência da bobina é maior que 8 Ω.
A potência dissipada pelo resistor Rs é igual a 50 W.
Adotando a tensão Vs como referência, o ângulo da impedância da bobina é menor que 60°.
Determine o valor de YT.
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Assinale a alternativa que corresponde a reposta.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
O valor do módulo da impedância da carga desconhecida é maior que 9 Ω.
O valor, em módulo, da corrente na linha é maior que 19 A.
O valor, em módulo, da corrente de fase da carga conhecida é menor que 7 A.
O fator de potência da segunda carga é igual a 0,6, atrasado.
O reativo total absorvido pela carga desconhecida é maior que 6,5 kVAr.
Uma carga equilibrada, ligada em triângulo, absorve 5 kW de um sistema trifásico cuja tensão eficaz da linha é igual a 400 V. Sendo o fator de potência da carga igual a 0,8, atrasado, é correto afirmar:
Se as três impedâncias da carga fossem ligadas em estrela o valor da potência aparente total absorvida seria igual a 1/3 do valor da ligação em triângulo.
O valor do módulo da corrente de fase na carga é menor que 5,0 A.
O valor da resistência da impedância é menor que 60 Ω.
A potência aparente trifásica absorvida pela carga é maior que 6,5 kVA.
O valor, em módulo, da queda de tensão sobre a indutância da impedância é maior que 250 V.
Um aluno encontrou uma bobina e quis determinar o valor de sua resistência interna Rbob e de sua indutância Lbob. Para tanto, conectou em série com a bobina uma resistência Rs = 10 Ω. Ele ligou o conjunto num varivolt e aplicou nele uma tensão de 36 V, eficazes, em 60 Hz. Com um voltímetro, mediu a tensão sobre o resistor, obtendo Vs = 20 V e sobre a bobina, obtendo Vbob = 22,4 V. Com os resultados obtidos fez os cálculos e concluiu que:
A tensão fasorial do varivolt deve ser escrita como Vvar = 36 /+40° V.
A bobina possui uma indutância menor que 30 mH.
A resistência da bobina é maior que 8 Ω.
A potência dissipada pelo resistor Rs é igual a 50 W.
Adotando a tensão Vs como referência, o ângulo da impedância da bobina é menor que 60°.
Determine o valor de YT.
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Assinale a alternativa que corresponde a reposta.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
Se as três impedâncias da carga fossem ligadas em estrela o valor da potência aparente total absorvida seria igual a 1/3 do valor da ligação em triângulo.
O valor do módulo da corrente de fase na carga é menor que 5,0 A.
O valor da resistência da impedância é menor que 60 Ω.
A potência aparente trifásica absorvida pela carga é maior que 6,5 kVA.
O valor, em módulo, da queda de tensão sobre a indutância da impedância é maior que 250 V.
Um aluno encontrou uma bobina e quis determinar o valor de sua resistência interna Rbob e de sua indutância Lbob. Para tanto, conectou em série com a bobina uma resistência Rs = 10 Ω. Ele ligou o conjunto num varivolt e aplicou nele uma tensão de 36 V, eficazes, em 60 Hz. Com um voltímetro, mediu a tensão sobre o resistor, obtendo Vs = 20 V e sobre a bobina, obtendo Vbob = 22,4 V. Com os resultados obtidos fez os cálculos e concluiu que:
A tensão fasorial do varivolt deve ser escrita como Vvar = 36 /+40° V.
A bobina possui uma indutância menor que 30 mH.
A resistência da bobina é maior que 8 Ω.
A potência dissipada pelo resistor Rs é igual a 50 W.
Adotando a tensão Vs como referência, o ângulo da impedância da bobina é menor que 60°.
Determine o valor de YT.
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Assinale a alternativa que corresponde a reposta.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
A tensão fasorial do varivolt deve ser escrita como Vvar = 36 /+40° V.
A bobina possui uma indutância menor que 30 mH.
A resistência da bobina é maior que 8 Ω.
A potência dissipada pelo resistor Rs é igual a 50 W.
Adotando a tensão Vs como referência, o ângulo da impedância da bobina é menor que 60°.
Determine o valor de YT.
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)
Assinale a alternativa que corresponde a reposta.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
YT=1,567 S< -50,194°
YT=0,195 S< -50,194°
YT=10,65 S< -45,65°
YT=1,567 S< +50,194°
YT=0,195 S< +50,194°
Seja o circuito paralelo mostrado na figura. A corrente fornecida pela fonte é dada por ig(t) = 5. cos (8.105 t) A. Equacionando o circuito é correto afirmar:
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
![](http://sga.uniube.br/images/uploads/5105/SEM09_Q4.jpg)
A corrente que circula pelo capacitor está adiantada da corrente da fonte de um ângulo maior que 50°.
A susceptância equivalente do circuito é indutiva e tem valor maior que 0,08 s.
Na construção do circuito equivalente, o valor da resistência equivalente é menor que 5,0 Ω.
A tensão instantânea, de regime permanente, sobre o indutor é dada por vL(t) = 44,76 cos (8.105 t - 10,2°) V.
O valor, do módulo, da tensão vo é menor que 50 V.
A figura mostra um resistor R = 2 Ω ligado em série com uma impedância Z, desconhecida. Do circuito sabe-se que o fator de potência é atrasado e que a potência média absorvida P = 300 W. É correto afirmar que:
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
![](http://sga.uniube.br/images/uploads/5105/M4_Q02.jpg)
A queda de tensão fasorial sobre a impedância tem módulo menor que 110 V.
A impedância Z é composta por um único elemento, resistivo, de valor igual a 31,3 Ω.
A potência aparente absorvida pela impedância Z é maior que 400 VA.
A impedância Z pode ser composta por dois, ou mais elementos, ligados em série ou em paralelo.
O ângulo θ° da corrente é negativo e menor que 32°.
Uma carga, com impedância Zc, absorve de uma fonte de tensão senoidal de 120 V, eficazes, 12 kVA, com fator de potência 0,856. Para a carga, é correto afirmar que:
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
A potência que realiza trabalho absorvida é menor que 10 kW.
A potência reativa absorvida tem valor menor que 6 kVAr.
Sua impedância possui valor igual 1,2 Ω, mas, não é possível afirmar se é capacitiva ou indutiva.
O ângulo da corrente que circula por ela é maior que 32°.
O valor de pico da corrente que circula é maior que 150 A.
Um sinal de tensão é dado por: v(t) = 250 sen (120.pi.t + 15°) V. Para o sinal, é correto afirmar que:
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
O valor eficaz da tensão é, aproximadamente, igual a 144 V.
Sua equação equivalente cossenoidal é escrita por v(t) = 250.cos (120.pi.t - 75°) V.
A frequência angular do sinal é igual a 60 rad/s.
O valor instantâneo da tensão, no tempo t = 0, é igual a 250 V.
O deslocamento angular do sinal corresponde a um tempo igual a 1,3 ms.
A figura mostra um motor elétrico que, quando ligado numa rede elétrica, cuja tensão alternada é descrita por v(t) = 120 sen(314,16t + 80°) V, fica sujeito à corrente elétrica alternada, descrita por i(t) = 5 cos(314,16t – 60°) A. Qual das afirmativas abaixo está correta.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.
![](http://sga.uniube.br/images/uploads/5105/Q04_fechada.jpg)
Um amperímetro digital ligado ao motor mostraria, em seu display, uma corrente igual a 3,535 A, caso fosse fabricado para funcionar em frequência igual a 50 Hz.
O defasamento angular entre os dois sinais é maior que 3,0 ms.
A equação instantânea da corrente está escrita de forma errada, pois, uma tensão senoidal não pode gerar uma corrente cossenoidal.
A corrente no motor atinge o primeiro valor máximo negativo no instante t1 positivo, equivalente a 220°.
Os valores máximos positivos dos sinais são coincidentes, em um determinado tempo.